Fluids I + Fluids II · one-page revision

Fluids in four verbs

A fluid pushes, flows, resists and clings. Every idea in both chapters fits under one of these verbs. For each idea you get one line, one formula, the trap to avoid, and the ways NEET asks about it. Answer the question in your head first, then tap to check.

21 ideas 21 traps 56 quick checks Full lesson: Fluids I → Full lesson: Fluids II →
★ Start here

The chapter on one map

If a question confuses you, first ask which verb it is about. That tells you which group of formulas to use.

Use this for a quick read-through. Keep answers hidden when you are testing yourself.
VERB 1 Fluids I · 9.1–9.2

It pushes: a fluid at rest

01 · Fluids I §9.1

Density

Density tells you how much mass is packed into each cubic metre.

Seen itOil floats on water because it is less dense.

\[ \rho=\frac{m}{V},\qquad \text{RD}=\frac{\rho}{\rho_{\text{water}}} \]

Mixing liquids: equal volumes → \(\dfrac{\rho_1+\rho_2}{2}\) · equal masses → \(\dfrac{2\rho_1\rho_2}{\rho_1+\rho_2}\)

TrapEqual masses do not give the simple average. The equal-mass answer is always the smaller one. Relative density has no unit.

How NEET asks it

NumEqual masses of liquids of density 2 and 3 g cm⁻³ are mixed. What is the density of the mixture?

\(\frac{2(2)(3)}{2+3}=2.4\) g cm⁻³. The tempting wrong answer is 2.5.

UnitThe relative density of mercury is 13.6. What is its density in SI units?

13.6 × 1000 = 13 600 kg m⁻³.

02 · Fluids I §9.2–9.2.1

Pressure

Pressure is force shared over an area. The same push on a smaller area gives a bigger pressure.

Seen itA sharp knife cuts, but a blunt one doesn't. A camel's wide feet don't sink into sand.

\[ P=\frac{F_\perp}{A}\qquad [\mathrm{ML^{-1}T^{-2}}],\ \ 1\ \text{Pa}=1\ \text{N m}^{-2} \]

TrapPressure is a scalar. At a point it is the same in every direction. The force a fluid at rest exerts on a surface is always normal (perpendicular) to that surface.

How NEET asks it

T / F“Pressure at a point in a fluid acts vertically downward.” Is this true or false?

False. Pressure has no direction; it acts equally in all directions at a point. (This was Q3 in your Test-05.)

DimPressure has the same dimensions as which of these: force, energy, energy per unit volume, or power?

Energy per unit volume: J m⁻³ = N m⁻² = [ML⁻¹T⁻²]. Stress has the same dimensions too.

03 · Fluids I §9.2.2

Pressure with depth

The deeper you go, the more liquid sits on top of you, so the pressure rises by ρgh. Only the vertical depth matters.

Seen itDams are built thicker at the bottom.

\[ P=P_0+\rho g h,\qquad P_2-P_1=\rho g\,\Delta h \]

TrapThe shape of the vessel and the amount of liquid do not matter. In a connected liquid at rest, all points at the same level have the same pressure.

How NEET asks it

ConceptThree vessels of different shapes have the same base area and are filled to the same height. How do the forces on their bases compare?

All three are equal. P = ρgh depends only on height, so F = PA is the same (the hydrostatic paradox).

NumWhat is the absolute pressure 10 m below a lake surface? (P₀ = 10⁵ Pa, g = 10)

10⁵ + 1000 × 10 × 10 = 2 × 10⁵ Pa, about 2 atm.

U-tubeIn a U-tube, a 10 cm column of oil balances an 8 cm column of water. Find ρ_oil.

Equal pressures at the interface level: ρ_oil × 10 = 1000 × 8, so ρ_oil = 800 kg m⁻³.

04 · Fluids I §9.2.3

Atmospheric and gauge pressure

We live at the bottom of an ocean of air. A pressure gauge reads only the pressure above atmospheric.

Seen itA drinking straw works because the atmosphere pushes the drink up the straw.

\[ P_{\text{atm}}=\rho_{\text{Hg}}\,g\,(0.76\text{ m})\approx1.013\times10^{5}\ \text{Pa},\qquad P_{\text{gauge}}=P-P_{\text{atm}} \]

Manometer rule: going down a column, add ρgh; going up, subtract ρgh.

TrapGas laws and bubble problems need absolute pressure. When atmosphere pushes on both sides (dam walls, lids), use gauge pressure.

How NEET asks it

NumA barometer uses water instead of mercury. How tall is its column?

h = 1.013 × 10⁵ / (1000 × 9.8) ≈ 10.3 m. (That is 13.6 × 76 cm.)

ConceptA tyre gauge reads 2 atm. What is the absolute pressure inside the tyre?

2 + 1 = 3 atm.

05 · Fluids I §9.2.4

Pascal's law and the hydraulic lift

Press on a trapped liquid and the extra pressure reaches every part of it undiminished. A small force on a small piston can lift a big load.

Seen itHydraulic brakes, car-service lifts and JCB arms.

\[ \frac{F_1}{A_1}=\frac{F_2}{A_2},\qquad A_1x_1=A_2x_2 \]

TrapIf diameters are given, square their ratio to get the force ratio. A hydraulic lift multiplies force, not work: the small piston moves much farther.

How NEET asks it

NumThe pistons have diameters of 2 cm and 20 cm. A 10 N push on the small piston supports what load?

(20/2)² = 100, so the load is 100 × 10 = 1000 N.

NumIn the same lift, the small piston is pushed down 50 cm. How far does the large piston rise?

50 / 100 = 0.5 cm, because the displaced volume is the same.

ConceptDoes an ideal hydraulic lift give out more work than you put in?

No. Work in = work out. It gains force by losing distance.

06 · Fluids I ★ Archimedes

Buoyancy and floating

A liquid pushes up with a force equal to the weight of the liquid the body pushes aside.

Seen itA steel ship floats, and only the tip of an iceberg shows above the sea.

\[ F_B=\rho_\ell V_{\text{sub}}\,g,\qquad \text{floating: }\frac{V_{\text{sub}}}{V}=\frac{\rho_{\text{body}}}{\rho_\ell} \]

Relative density of a body = Wair ÷ (Wair − Wwater), i.e. weight ÷ loss of weight.

TrapUse the submerged volume, not the whole volume. Once a body is fully under the surface, the buoyant force doesn't change with depth.

How NEET asks it

NumIce (ρ = 900 kg m⁻³) floats in water. What fraction of it is above the water?

Fraction submerged is 900/1000 = 9/10, so 1/10 is above.

NumA stone weighs 10 N in air and 8 N in water. What is its relative density?

10 / (10 − 8) = 5.

ConceptAn ice cube floating in a glass of water melts. What happens to the water level?

It stays the same. The meltwater exactly fills the volume the ice was displacing.

NumA block floats with 60% of its volume in water and 75% of its volume in oil. Find ρ_oil.

The block's density is 600 kg m⁻³, so ρ_oil = 600 / 0.75 = 800 kg m⁻³.

VERB 2 Fluids I · 9.3–9.4

It flows: a fluid in motion

07 · Fluids I §9.3

Continuity

Liquid can't pile up inside a pipe. Where the pipe narrows, the liquid has to speed up.

Seen itPut your thumb over a hose and the water shoots out faster.

\[ A_1v_1=A_2v_2\;(=Q),\qquad v\propto\frac{1}{A}\propto\frac{1}{d^{2}} \]

Streamline (steady) flow: the velocity at each point does not change with time, and streamlines never cross.

TrapHalving the diameter cuts the area to ¼, so the speed becomes 4 times larger, not 2 times.

How NEET asks it

NumA pipe's diameter halves. How does the speed in the narrow part compare?

It is 4 times the speed in the wide part.

Why?Why does a stream of water from a tap get thinner as it falls?

Gravity speeds the water up. Since Av is constant, the area A must decrease.

ConceptCan two streamlines cross each other?

No. At the crossing point the fluid would have two velocities at once.

08 · Fluids I §9.4

Bernoulli's principle

Energy per unit volume stays constant along the flow, so wherever a fluid moves faster, its pressure is lower.

Seen itStorms blow roofs off. Two boats moving side by side are pulled towards each other.

\[ P+\tfrac12\rho v^{2}+\rho g h=\text{constant} \]

The three terms are pressure energy, kinetic energy and potential energy, each per unit volume (in Pa).

TrapBernoulli applies only to ideal flow: incompressible, non-viscous, steady, and along a streamline. It is the law of energy conservation.

How NEET asks it

NumIn a horizontal pipe, water speeds up from 2 m/s to 4 m/s. By how much does the pressure drop?

½ × 1000 × (16 − 4) = 6000 Pa.

ConceptBernoulli's theorem is a statement of the conservation of what?

Energy (per unit volume of the fluid).

Why?Strong wind blows over a roof. Which way is the net force on the roof?

Upward. The fast air above has lower pressure than the still air inside the house.

09 · Fluids I §9.4.1

Torricelli: speed of efflux

Water comes out of a hole as fast as a stone would be moving after falling from the water surface down to the hole.

Seen itOn a leaking tank, water from the lower holes spurts out faster.

\[ v=\sqrt{2gh},\qquad R=2\sqrt{h(H-h)},\qquad R_{\max}=H\ \text{at}\ h=\tfrac H2 \]

h = depth of the hole below the surface; H = height of the water surface above the ground.

TrapMeasure h down from the free surface, not up from the bottom. The efflux speed doesn't depend on the liquid's density.

How NEET asks it

NumA hole is 5 m below the water surface. What is the efflux speed? (g = 10)

√(2 × 10 × 5) = 10 m/s.

MaxA tank is filled to height H. Where should the hole be for maximum range, and what is that range?

At depth H/2 (halfway up). The maximum range is H.

PairA tank is filled to 10 m. A hole at 2 m depth gives the same range as a hole at what other depth?

8 m. Depths h and H − h always give equal ranges.

10 · Fluids I ★

Venturimeter and Pitot tube

Narrow the pipe and measure how much the pressure drops. The size of the drop tells you how fast the fluid flows.

Seen itPerfume sprayers, carburettors and Bunsen burners all use this.

\[ P_1-P_2=\tfrac12\rho\left(v_2^{2}-v_1^{2}\right),\quad A_1v_1=A_2v_2 \]

Manometer reading: ΔP = ρmgh. Pitot tube: stagnation − static = ½ρv².

TrapThe throat has the highest speed and the lowest pressure. A venturimeter needs continuity and Bernoulli together.

How NEET asks it

NumWater flows through a venturimeter whose main area is twice its throat area. The pressure difference is 3000 Pa. Find the speed in the main pipe.

v₂ = 2v₁, so 3000 = ½ × 1000 × (4v₁² − v₁²) = 1500 v₁². This gives v₁ = √2 ≈ 1.4 m/s.

Why?How does a perfume sprayer lift the liquid?

Fast air over the top of the tube lowers the pressure there, and atmospheric pressure pushes the liquid up.

11 · Fluids I §9.4.2

Dynamic lift and the Magnus effect

Air moves faster over the top of a wing, so the pressure on top is lower and the wing is pushed up.

Seen itAeroplane wings, and a spinning cricket ball that swerves (the Magnus effect).

\[ F=\Delta P\,A=\tfrac12\rho\left(v_{\text{top}}^{2}-v_{\text{bottom}}^{2}\right)A \]

TrapA spinning ball moves towards the side where its spin adds to the airflow. The air is faster there, so the pressure is lower. Reverse the spin and it curves the other way.

How NEET asks it

NumA wing of area 10 m² has air moving at 60 m/s above it and 50 m/s below it. Find the lift. (ρ = 1.2 kg m⁻³)

½ × 1.2 × (3600 − 2500) × 10 = 6600 N.

ConceptWhat happens to the path of a ball thrown with topspin?

It dips sooner. Topspin makes the air faster below the ball, so the net push is downward.

12 · Fluids I ★

Accelerating containers

In an accelerating tank, the water surface tilts until it is perpendicular to the “effective gravity”.

Seen itTea sloshes to the back of the cup when a bus starts.

\[ \tan\theta=\frac{a}{g}\ \ (\text{sideways }a),\qquad P=P_0+\rho(g+a)h\ \ (\text{lift accelerating up}) \]

Free fall: geff = 0, so there is no pressure difference with depth and no buoyancy.

TrapThe surface rises at the back, on the side opposite the acceleration. In a lift, the fraction of a floating block under water does not change, because its weight and the buoyancy scale together.

How NEET asks it

NumA truck carrying a tank of water accelerates at g/√3. What angle does the water surface make with the horizontal?

tan θ = 1/√3, so θ = 30°.

ConceptA block floats half-submerged in a lift. The lift then accelerates upward. How much of the block is submerged now?

Still half.

ConceptWhat is the buoyant force on a ball held under water in a freely falling container?

Zero. With geff = 0 there is no pressure difference.

VERB 3 Fluids II · 9.5

It resists: liquid friction

13 · Fluids II §9.5

Viscosity

Viscosity is friction between liquid layers as they slide over each other. Honey has a lot of it; water has a little.

Seen itHoney pours slowly, and engine oil keeps metal parts from rubbing.

\[ F=\eta A\frac{dv}{dx},\qquad [\eta]=[\mathrm{ML^{-1}T^{-1}}] \]

SI unit Pa·s (N s m⁻²); 1 poise = 0.1 Pa·s.

TrapWhen heated, liquids become less viscous but gases become more viscous. Convert poise to Pa·s (÷ 10) before you substitute.

How NEET asks it

NumA plate of area 0.1 m² slides at 0.1 m/s over a 1 mm oil film (η = 1 Pa·s). What force is needed?

1 × 0.1 × 0.1 / 0.001 = 10 N.

ConceptWhat happens to the viscosity of air when it is heated?

It increases. For liquids it would decrease.

14 · Fluids II ★

Poiseuille: flow through a tube

Flow through a thin tube depends on the fourth power of its radius.

Seen itWhen an artery narrows a little, blood flow drops a lot.

\[ Q=\frac{\pi P r^{4}}{8\eta\, l},\qquad R_{\text{flow}}=\frac{8\eta l}{\pi r^{4}} \]

Combine tubes like electrical resistors: add R in series, and add 1/R in parallel.

TrapBecause of the fourth power, halving r divides Q by 16. The speed at the axis is twice the mean speed.

How NEET asks it

NumA tube's radius is doubled while the pressure difference stays the same. What happens to the flow rate?

It becomes 2⁴ = 16 times larger.

SeriesTwo tubes of equal length, with radii r and r/2, are joined in series. Which one takes most of the pressure drop?

The thin one has 16 times the resistance, so it takes 16/17 of the total pressure drop.

15 · Fluids II §9.5.1

Stokes' law and terminal velocity

A falling ball speeds up until drag plus buoyancy balance its weight. After that it falls at a constant speed, the terminal velocity.

Seen itRaindrops land gently instead of hitting like bullets.

\[ F=6\pi\eta r v,\qquad v_t=\frac{2r^{2}(\rho-\sigma)g}{9\eta} \]

ρ = density of the ball, σ = density of the liquid.

TrapUse (ρ − σ), never ρ alone. If σ > ρ, as for an air bubble, vt points upward.

How NEET asks it

NumA ball's radius is doubled. What happens to its terminal velocity?

It becomes 4 times larger (vt ∝ r²).

Merge8 identical raindrops merge into one drop. How does the new terminal speed compare?

The radius doubles (81/3 = 2), so the speed is 4 times larger. In general, n drops give n2/3 times the speed.

ForceA ball moves at terminal velocity through a liquid that is half as dense as the ball. What is the viscous force?

Fv = W − B = Mg − Mg/2 = Mg/2.

16 · Fluids II ★

Reynolds number

One number tells you whether a flow moves in calm layers or chaotic swirls. It compares inertia with viscosity.

Seen itSmoke from an incense stick rises smoothly at first, then breaks into swirls.

\[ Re=\frac{\rho v d}{\eta}\quad(\text{no unit}),\qquad v_c=\frac{Re\,\eta}{\rho d} \]

Coaching values: Re < 1000 streamline; Re > 2000 turbulent.

TrapHigher viscosity gives a lower Re, so the flow stays streamline up to a higher speed. Re is a pure number with no dimensions.

How NEET asks it

DimWhat are the dimensions of Reynolds number?

None: [M⁰L⁰T⁰].

ConceptWhich liquid stays streamline up to a higher speed in the same pipe: a more viscous one or a less viscous one?

The more viscous one, because vc ∝ η.

VERB 4 Fluids II · 9.6

It clings: the liquid's skin

17 · Fluids II §9.6.1

Surface tension

A liquid surface behaves like a stretched elastic skin. T is the pull on each metre of its edge.

Seen itA pond skater walks on water, a steel needle can float, and raindrops are round.

\[ T=\frac{F}{L},\qquad \text{N m}^{-1}=\text{J m}^{-2},\quad [\mathrm{MT^{-2}}] \]

TrapA soap film has two surfaces, so F = 2TL. T decreases as temperature rises. Soap lowers T; dissolved salt (NaCl) raises it.

How NEET asks it

NumWhat extra force is needed to lift a thin wire ring of radius r off a water surface?

There are two contact circles, inside and outside, each 2πr long. F = 2 × 2πr × T = 4πrT.

Why?Why are small drops spherical?

Surface tension makes the surface area as small as possible, and a sphere has the least area for a given volume.

DimSurface tension has the same dimensions as which quantity: force, spring constant, or pressure?

Spring constant (N/m): [MT⁻²].

18 · Fluids II §9.6.2

Surface energy

Making new surface costs energy: T joules for every square metre of new surface.

Seen itBlowing a big soap bubble takes effort.

\[ W=T\,\Delta A\quad(\text{film: }2T\Delta A),\qquad W_{\text{bubble}}=8\pi r^{2}T \]

TrapWhen drops merge, the area shrinks and energy is released, which warms the drop. Splitting a drop needs work. Count both surfaces of a film.

How NEET asks it

NumHow much work does it take to blow a soap bubble of radius r?

2 surfaces × 4πr² × T = 8πr²T.

NumA drop of radius R splits into 1000 equal droplets. How much work is done?

Each droplet has r = R/10. ΔA = 1000 × 4π(R/10)² − 4πR² = 36πR², so W = 36πR²T.

ConceptMany tiny drops merge into one big drop. What happens to its temperature?

It rises, because surface energy is released.

19 · Fluids II §9.6.3

Angle of contact

The contact angle shows whether a liquid “likes” a solid. Below 90° it spreads out and wets the solid; above 90° it beads up.

Seen itWater beads up on a lotus leaf or a raincoat but spreads out on clean glass.

θ < 90°: wets the solid, concave meniscus, rises in a capillary. Water–glass ≈ 0°.

θ > 90°: doesn't wet, convex meniscus, falls in a capillary. Mercury–glass ≈ 140°.

TrapDetergents lower θ, so the liquid wets better. Waterproofing agents make θ obtuse.

How NEET asks it

ConceptWhat shape is the mercury meniscus in a glass tube?

Convex, because θ > 90°.

ConceptA waterproofing agent is applied to cloth. How does it change the contact angle?

It makes the angle obtuse (more than 90°).

20 · Fluids II §9.6.4

Drops and bubbles: excess pressure

A curved surface squeezes whatever is inside it. The smaller the radius, the larger the extra pressure inside.

Seen itA balloon is hardest to blow at the very start, when it is smallest.

\[ \text{drop / air bubble: }\frac{2T}{r},\qquad \text{soap bubble: }\frac{4T}{r} \]

Air bubble at depth h: Pinside = P₀ + ρgh + 2T/r.

TrapIf two soap bubbles are connected, air flows from the smaller one into the larger one. A soap bubble has two surfaces; an air bubble inside a liquid has only one.

How NEET asks it

NumA soap bubble has r = 1 cm and T = 0.03 N/m. What is the excess pressure inside it?

4 × 0.03 / 0.01 = 12 Pa.

DoubleTwo soap bubbles of radii r₁ < r₂ are stuck together. What is the radius of the film between them?

r₁r₂ / (r₂ − r₁). The film bulges into the bigger bubble.

MergeSoap bubbles of radii 3 cm and 4 cm merge in vacuum at constant temperature. Find the new radius.

R² = r₁² + r₂² = 9 + 16, so R = 5 cm.

21 · Fluids II §9.6.5

Capillary rise

In a thin tube, the surface skin pulls water upward. The narrower the tube, the higher the water climbs.

Seen itOil climbs a lamp wick, blotting paper soaks up ink, and water rises through soil and plants.

\[ h=\frac{2T\cos\theta}{r\rho g},\qquad h\,r=\text{constant} \]

TrapIf the tube is shorter than h, water does not overflow; the meniscus just flattens. In a tilted tube the vertical height stays h, and the length along the tube is h/cos α.

How NEET asks it

NumA capillary tube's radius is halved. What happens to the rise h?

h doubles.

MassA tube's radius is doubled. How does the mass of water raised change?

m = ρπr²h ∝ r² × (1/r) = r, so the mass doubles.

LiftA capillary tube in water is inside a lift that falls freely. What happens to the water?

With geff = 0 nothing limits the rise, so water climbs to the top of the tube.

ConceptA glass capillary is dipped in mercury. What happens to the mercury level inside it?

It falls below the outside level, because θ > 90° makes cos θ negative.

★ Exam

Question decoder: words → formula

NEET questions give away their pattern in a few key words. Read the left side, cover the right side, and say which tool you would use.

Says same level, U-tube or manometerEqual pressure at one level; walk the columns adding or subtracting ρgh · 03
Says floats with … outside or fraction submergedVsub/V = ρbody/ρliquid · 06
Says weighs … in air and … in waterRD = weight ÷ loss of weight · 06
Says pistons, hydraulic or brakesF ∝ A ∝ d²; work in = work out · 05
Says pipe narrows or diameter halved (speed)Av = constant, v ∝ 1/d² · 07
Says roof, storm, wing or speed and pressureBernoulli, then F = ΔP·A · 08 11
Says hole in a tank, efflux or rangev = √(2gh), R = 2√(h(H−h)) · 09
Says throat or venturimeterContinuity + Bernoulli together · 10
Says truck accelerates or lift moving upEffective gravity: tan θ = a/g, or g → g ± a · 12
Says plate on an oil film or layersF = ηAv/d (convert poise ÷ 10) · 13
Says flow rate through a narrow tubeQ ∝ r⁴ · 14
Says falls through a liquid at constant speed or drops coalescevt ∝ r²(ρ − σ); n drops → × n2/3 · 15
Says laminar or turbulent or critical velocityRe = ρvd/η · 16
Says ring, needle or frame pulled off waterF = T × total contact length (count both sides) · 17
Says split into n drops or blow a bubbleW = T·ΔA (× 2 for a film) · 18
Says excess pressure or bubble at depth2T/r for drops and air bubbles; 4T/r for soap bubbles · 20
Says rise in a capillary or meniscush = 2T cos θ/(rρg), hr = constant · 21
★ Ratio drill

Change the radius: what happens?

Ratio questions are the easiest marks in fluids. Each formula depends on the radius through a different power. Pick a change, guess every multiplier, then look.

Flow rate through a tubeQ ∝ r⁴×16Poiseuille
Terminal velocity of a ballvt ∝ r²×4Stokes
Force on the big piston (its radius changes)F ∝ r²×4Pascal
Surface energy of a dropE = 4πr²T×4Surface energy
Stokes drag at the same speedF = 6πηrv×2Stokes
Mass of water in a capillarym ∝ r²h ∝ r×2Capillarity
Capillary riseh ∝ 1/r×1/2Capillarity
Excess pressure in a bubbleΔP ∝ 1/r×1/2Bubbles
Flow speed in that part of the pipev ∝ 1/r²×1/4Continuity
Pressure needed for the same flow rateP ∝ 1/r⁴×1/16Poiseuille